2v^2-n-4=2

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Solution for 2v^2-n-4=2 equation:


Simplifying
2v2 + -1n + -4 = 2

Reorder the terms:
-4 + -1n + 2v2 = 2

Solving
-4 + -1n + 2v2 = 2

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + -1n + 4 + 2v2 = 2 + 4

Reorder the terms:
-4 + 4 + -1n + 2v2 = 2 + 4

Combine like terms: -4 + 4 = 0
0 + -1n + 2v2 = 2 + 4
-1n + 2v2 = 2 + 4

Combine like terms: 2 + 4 = 6
-1n + 2v2 = 6

Add '-2v2' to each side of the equation.
-1n + 2v2 + -2v2 = 6 + -2v2

Combine like terms: 2v2 + -2v2 = 0
-1n + 0 = 6 + -2v2
-1n = 6 + -2v2

Divide each side by '-1'.
n = -6 + 2v2

Simplifying
n = -6 + 2v2

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